Has()

template<typename T >

bool Spices::ResourcePool< T >::Has ( const std::string & name )

inlinestatic

Determine if specific resource is exist.

Parameters

[in]

name

Resource Name.

Returns

Returns true if exist.

Definition at line 167 of file ResourcePool.h.

    {
        SPICES_PROFILE_ZONE;
 
        std::shared_lock<std::shared_mutex> lock(m_Mutex);
 
        if (m_Resources.find(name) != m_Resources.end()) return true;
        return false;
    }

Referenced by Spices::ResourcePool< T >::Access().